Cleveland Browns linebacker D’Qwell Jackson has been named AFC Defensive Player of the Week for games played on November 22-26, the NFL announced today.
Jackson totaled a team-high nine tackles and had a hand in two turnovers as he forced one fumble and recovered another during the team’s 20-14 victory against the Pittsburgh Steelers at Cleveland Browns Stadium last Sunday. Jackson led the Browns’ defensive unit which limited the Steelers to 242 total net yards, including just 49 rushing, which marked Cleveland’s lowest rushing total allowed since 2003. In total, the Browns defense forced eight turnovers, which were the most by an NFL team since 2001 and the most by the Browns since 1989.
This is the first AFC Defensive Player of the Week award for Jackson. He is the first Brown to win AFC Defensive Player of the Week honors since linebacker David Bowens in Week 7 of the 2010 season. Jackson was named AFC Defensive Player of the Month in September of 2011.
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